Chemistry - CHEMICAL BONDING Question with Solution | TestHub

As the number of lone pairs of electrons increases, bond angle decreases. Thus, the order of bond angle is

$\begin{array}{ccccc}\text{N}{\text{H}}_4^{+}& >& \text{N}{\text{H}}_3& >& \text{N}{\text{H}}_2^{-}\\ \left(\text{no Ip}\right)& & \left(\text{1 Ip}\right)& & \left(\text{2 IP}\right)\end{array}$