Chemistry - CHEMICAL BONDING Question with Solution | TestHub

M.O. Electronic configuration.

$O_2=\sigma 1s^2<\stackrel{*}{\sigma }1s^2<\sigma 2s^2<\stackrel{*}{\sigma }2s^2<\sigma 2p_z^2<\pi 2p_y^2=\pi 2p_x^2<\stackrel{*}{\pi }2p_y^1=\stackrel{*}{\pi }2p_x^1$Paramagnetic
${{\mathrm{O}}_2}^{-2}$=σ1 s ² < σ * 1 s ² <σ2 s ² < σ * 2 s ² <σ2 p _z ² <π2 p _y ² =π2 p ²_x < π * 2 p _y ² = π * 2 p _x ² Diamagnetic
$C_2=\sigma 1s^2<\stackrel{*}{\sigma }1s^2<\sigma 2s^2<\stackrel{*}{\sigma }2s^2<\pi 2p_x^2=\pi 2p_y^2$Diamagnetic

$N_2=\sigma 1s^2<\stackrel{*}{\sigma }1s^2<\sigma 2s^2<\stackrel{*}{\sigma }2s^2<\pi 2p_x^2=\pi 2p_y^2<\sigma 2p_z^2$Diamagnetic

 ${\mathrm{O}}_2$has unpaired e^-so it is paramagnetic.