If the dipole moment of AB molecule is given by 1.6 D and A–B the bond length is 1 A o then % covalent character of the bond is

μ C a l = 4.8 × 1 0 - 10 e . s . u × 1 0 - 8 c m 4.8 × 10 − 18 esu × cm = 4.8 D Hence, % ionic character = 1 .6 4 .8 × 100 = 33.33 %

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Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGDipole MomentEasy2 minPYQ_2020

ChemistryEasysingle choice

If the dipole moment of AB molecule is given by 1.6 D and A–B the bond length is $1 \overset{o}{A}$ then % covalent character of the bond is

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Answer:

Solution:

$μ_{C a l} = 4.8 \times 1 0^{- 10} e . s . u \times 1 0^{- 8} c m$
$4.8 \times 10^{- 18} esu × cm$
$= 4.8 D$
Hence, $% ionic character = \frac{1 .6}{4 .8} × 100$
$= 33.33 %$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:Dipole Moment

⏱ 2mℹ️ Source: PYQ_2020

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