Home
PYQ PracticeFree
JEE Rank Predictor
Answer Key

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGMOTMedium2 minPYQ_2018

ChemistryMediumsingle choice

In the molecular orbital diagram for the molecular ion $N_{2}^{+}$ , the number of electrons in the $σ_{2 p}$ molecular orbital is

Options:

Answer:

Solution:

$N_{2}^{+} \to σ 1 s^{2}, \overset{*}{σ} 1 s^{2}, σ 2 s^{2}, \overset{*}{σ} 2 s^{2}, [π 2 p_{x}^{2} = π 2 p_{y}^{2}], σ 2 p_{z}^{1}$

The number of electron in $σ 2 p_{z}$ is $1$ .

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:MOT

⏱ 2mℹ️ Source: PYQ_2018

Doubts & Discussion

Loading discussions...