Compound AB x 1 y is a non planar polar compound where "A" is central atom (wherever applicable). "B" is surrounding atom & L is lone pair on central atom. Element "A" exist as a liquid in nature.

Question

Compound AB x ​ 1 y ​ is a non planar polar compound where "A" is central atom (wherever applicable). "B" is surrounding atom & L is lone pair on central atom. Element "A" exist as a liquid in nature. Both A − and B − has size less than hydride ion. Also A & B belong to same group of p-block. Bond length as well as bond strength of A 2 is more than that of B 2 . Which is/are correct in accordance with the above information.

TestHub · Accepted Answer

A is Bromine (Br) (liquid halogen) and B is Fluorine (F), because Br₂ has both a longer bond length and higher bond strength than F₂ due to interelectronic repulsions in F₂.

For (B): BrF₅ ( $x = 5, y = 1$ ) has a square pyramidal geometry, which is non-planar and polar, perfectly satisfying the compound's description.

For (C): BrF ( $x = 1, y = 3$ ) is a diatomic molecule, making it inherently planar and polar.

For (D): BrF₇ ( $x = 7, y = 0$ ) does not exist due to the steric hindrance of accommodating seven fluorine atoms around the smaller bromine atom.

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