Molecule AB has a bond length of 1.617 Å and a dipole moment of 0.38 D. The fractional charge on each atom(absolute magnitude) is: ( e 0 = 4.802 × 10 - 10 e s u )

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Assuming complete separation of charges (i.e. +e, -e on two ends)

$μ = (4.802 \times 10^{- 10} e s u) \times (1.617 \times 10^{- 8} c m)$

$= 7.76 \times 10^{- 18} e s u . c m = 7.76 D$

Fractional charge on dipole ends $= \frac{0.38}{7.76} ≅ 0.05$

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