Chemistry - CHEMICAL BONDING Question with Solution | TestHub

i. Hybridization of$\mathrm{N}{\mathrm{H}}_3\mathrm{ }\left[\mathrm{\sigma }=3,\mathrm{ }\mathrm{l}\mathrm{p}=1\right]$

$\mathrm{s}{\mathrm{p}}^3$geometry : Tetrahedral



ii. Structures of$\mathrm{X}\mathrm{e}{\mathrm{F}}_4$is square planar.



Structure of$\mathrm{X}\mathrm{e}{\mathrm{O}}_4$is tetrahedral



So$\mathrm{X}\mathrm{e}{\mathrm{F}}_4$and$\mathrm{X}\mathrm{e}{\mathrm{O}}_4$are not isostructural.

iii. Structure of$\mathrm{S}\mathrm{i}\mathrm{C}{\mathrm{l}}_4$is tetrahedral.



Structure of${\mathrm{P}\mathrm{C}\mathrm{l}}_4^{+}$is tetrahedral.



iv. Diamond and SiC both are isostructural because both have tetrahedral arrangement and central atom is$\mathrm{s}{\mathrm{p}}^3$hybridized.