Chemistry - CHEMICAL BONDING Question with Solution | TestHub

The bond order of ${\mathrm{N}}_2,{\mathrm{O}}_2$, and ${\mathrm{O}}_2^{-}$are respectively 3,2 and $1.5$ Since higher bond order implies higher bond dissociation energy hence the correct order will be $${\mathrm{N}}_2>{\mathrm{O}}_2>{\mathrm{O}}_2^{-}$$