Chemistry - CHEMICAL BONDING Question with Solution | TestHub

$\dot{\mathrm{C}}{\mathrm{H}}_3$ (methyl free radical) has planar structure with $s{p}^2$ hybridisation of ' $\mathrm{C}$ ' atom. The odd electron is present in unhybridised $2p_z$ orbital. $\oplus$ ${\mathrm{CH}}_3$ (methyl carbonium ion) has also trigonal planar structure $\left(s{p}^2\right)$. $\stackrel{\ominus }{{\mathrm{CH}}_3}$ (methyl carbanion) has tetrahedral structure $\left(s{p}^3\right)$ and one of the hybrid orbitals contains the lone pair of electrons.