Chemistry - CHEMICAL BONDING Question with Solution | TestHub

${\mathrm{XeOF}}_4$

$\mathrm{S}.\mathrm{N}=\frac{1}{2}\left(8+4\right)=6={\mathrm{sp}}^3{\mathrm{d}}^2$ square pyramidal

${\mathrm{XeO}}_3$

$\frac{1}{2}\left(8\right)=4={\mathrm{sp}}^3$ Pyramidal

${\mathrm{XeF}}_6$

$\frac{1}{2}\left(8+6\right)=7={\mathrm{sp}}^3{\mathrm{d}}^3$ distorted octahedral

${\mathrm{XeF}}_2$

$\frac{1}{2}\left(8+2\right)=5={\mathrm{sp}}^3\mathrm{d}$ linear