Chemistry - Carboxylic acid and their Derivatives Question with Solution | TestHub

$$\begin{gathered} \text{displaylines}\mathrm{A}={\mathrm{LiAlH}}_4,\mathrm{B}={\mathrm{NaOH}}_{(\mathrm{aq})}{ \\ }_{} \end{gathered}$$

$C=N{H}_2-N{H}_2$/KOH ,  ethylene glycol

$\mathrm{A}={\mathrm{LiAlH}}_4,\mathrm{B}={\mathrm{NaOH}}_{(\mathrm{alc})},\mathrm{C}=\mathrm{Zn}/\mathrm{HCl}$

$\mathrm{A}=\mathrm{DIBAL}-\mathrm{H},\mathrm{B}={\mathrm{NaOH}}_{(\mathrm{aq})}$,

$C=N{H}_2-N{H}_2$/KOH ,  ethylene glycol

$\mathrm{A}=$ DIBAL-H, $\mathrm{B}={\mathrm{NaOH}}_{(\mathrm{alc})},\mathrm{C}=\mathrm{Zn}/\mathrm{HCl}$