Chemistry - Carboxylic acid and their Derivatives Question with Solution | TestHub

$2\mathrm{P}+3{\mathrm{Br}}_2\to 2{\mathrm{PBr}}_3$

Number of moles in $1\mathrm{gm}$ of $\left(\mathrm{R}\right)=\frac{1}{250}$

using Carius method all the Br will be converted into AgBr. So, using POAC method

Number of moles of $\mathrm{AgBr}$ formed from $\left(\mathrm{R}\right)=\frac{2}{250}$

Mass of $\mathrm{AgBr}$ formed $=\frac{2\times 188}{250}=1.50\mathrm{gm}$