Chemistry - Carboxylic acid and their Derivatives Question with Solution | TestHub

$\underset{\begin{array}{c}\left(\text{A}\right)\\ \text{Oxalic}\text{acid}\end{array}}{{\text{H}}_{\text{2}}{\text{C}}_{\text{2}}{\text{O}}_{\text{4}}}\text{+}{\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}\to \underset{\begin{array}{c}\left(\text{B}\right)\\ \text{Neutral}\end{array}}{{\text{H}}_{\text{2}}\text{O}}\text{+}\underset{\begin{array}{c}\left(\text{C}\right)\\ \text{Acidic}\end{array}}{{\text{CO}}_{\text{2}}}\text{+}\underset{\begin{array}{c}\left(\text{D}\right)\\ \text{Diatomic}\text{oxide}\\ \end{array}}{\text{CO}}$
$\mathrm{C}\mathrm{O}+\mathrm{C}{\mathrm{l}}_2\to \underset{\left(\mathrm{E}\right)}{\mathrm{C}\mathrm{O}\mathrm{C}{\mathrm{l}}_2}$
${\text{COCl}}_{\text{2}}\text{+}{\text{2NH}}_{\text{3}}\to \underset{\begin{array}{c}\left(\text{F}\right)\\ \text{Urea}\end{array}}{{\text{NH}}_{\text{2}}{\text{CONH}}_{\text{2}}}\text{+}\text{2HCl}$