Chemistry - Carboxylic acid and their Derivatives Question with Solution | TestHub

${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Br}+\mathrm{Mg},{\mathrm{CO}}_2$dry ether$/{\mathrm{H}}_3{\mathrm{O}}^{+}$

${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_3+{\mathrm{KMnO}}_4\left(\mathrm{Heat}\right),{\mathrm{OH}}^{-}/{\mathrm{H}}_3{\mathrm{O}}^{+}$

${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CCl}}_3+{\mathrm{OH}}^{-}/{\mathrm{H}}_3{\mathrm{O}}^{+}$

${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{COCH}}_3+{\mathrm{OI}}^{-}/{\mathrm{H}}_3{\mathrm{O}}^{+}$