Chemistry - Carbonyl compounds Question with Solution | TestHub

Electronic configuration of$\mathrm{N}\mathrm{i}=4{\mathrm{s}}^{2}3{\mathrm{d}}^8$.
$\mathrm{C}\mathrm{O}$is strong ligand causes inward pairing, thus it is$\mathrm{s}{\mathrm{p}}^3$hybridised.
$\mathrm{N}\mathrm{i}(\mathrm{C}\mathrm{O}{)}_4$is tetrahedral and diamagnetic