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Chemistry - Carbonyl compounds Question with Solution | TestHub

ChemistryCarbonyl compoundsMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

For the complex with molecular formula $C r C l_{3} . 6 H_{2} O$ 0.1, mole of the complex when treated with excess of $A g N O_{3}$ gave 28.7 g of white precipitate of AgCl (Molar mass = 143.5 g). The formula of the complex would be

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Solution:

$\underset{0.1 mol}{{CrCl}_{3} .6 H_{2} O} + {AgNO}_{3} (excess) \to \underset{28.7 g}{AgCl}$
No. of moles of $A g C l = \frac{28.7}{143.5} \approx 0.2 m o l$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Carbonyl compoundsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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