On hydrolysis of a "compound", two compounds are obtained, One of which on treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one r

Question

On hydrolysis of a "compound", two compounds are obtained, One of which on treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one reduces Tollen's reagent and Fehling's solution. The "compound" is:NEET 2013 (Karnataka)

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Answer:

A

Solution:

$CH_{3} - CH_{2} - CH_{2} - NC + 2 H_{2} O \to$ $CH_{3} - CH_{2} - CH_{2} - NH_{2} + HCOOH$

TestHub · Accepted Answer

CH 3 ​ − CH 2 ​ − CH 2 ​ − NC + 2 H 2 ​ O → CH 3 ​ − CH 2 ​ − CH 2 ​ − NH 2 ​ + HCOOH

Chemistry - Carbonyl compounds Question with Solution | TestHub

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