Chemistry - Biomolecules Question with Solution | TestHub

ChemistryBiomoleculesAMINO ACIDMedium2 minQB

ChemistryMediumsingle choice

$N + H_{3} - CH (R) - CO_{2} H$ has its $Ka_{1} = 1 0^{- 7}$ . The isoelectric point of the $α$ -amino acid occur at $pH = 8.2$ hence $pKa_{2}$ of the conjugate acid of $α$ -amino acid is equal to

Options:

Answer:

Solution:

Isoelectric pH of a $aminoacid = \frac{p K _{a}^{1} + p K _{a}^{2}}{2}$

$∴ 8.2 = \frac{7 + p K _{a}^{2}}{2}$

$\Rightarrow p K a_{2} = 16.4 - 7 = 9.4$ Ans:A]

Stream:JEESubject:ChemistryTopic:BiomoleculesSubtopic:AMINO ACID

⏱ 2mℹ️ Source: QB

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