Chemistry - Biomolecules Question with Solution | TestHub

Glucose on oxidation with dilute nitric acid (${\text{HNO}}_3$) yields a dicarboxylic acid known as saccharic acid.

Dilute ${\text{HNO}}_3$ is a strong oxidizing agent that oxidizes both the terminal aldehyde group ($-\text{CHO}$) and the terminal primary alcohol group ($-{\text{CH}}_2\text{OH}$) of glucose into carboxylic acid groups ($-\text{COOH}$).

$\text{CHO}-(\text{CHOH}{)}_4-{\text{CH}}_2\text{OH}\stackrel{{\text{dil. HNO}}_3}{\to }\text{COOH}-(\text{CHOH}{)}_4-\text{COOH}$

Thus, the product formed is saccharic acid.

Answer: Saccharic acid