Not considering the electronic spin, the degeneracy of the first excited state of $Be^{3 +}$ is 4 . What is the degeneracy of the third excited state of $Be^{2 +}$ ?
[Given: atomic number of Be = 4 ]

Question

Not considering the electronic spin, the degeneracy of the first excited state of Be 3 + is 4 . What is the degeneracy of the third excited state of Be 2 + ? [Given: atomic number of Be = 4 ]

TestHub · Accepted Answer

Be 3 + is hydrogen like, i.e, energy depends only on n , while Be 2 + is a multielectron system and hence energy depends on ( n + l ) value. The third excited state of Be 2 + is 3s orbital.

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