Chemistry - Atomic Structure Question with Solution | TestHub
ChemistryAtomic StructureBohr's Atomic ModelEasy2 minQB
ChemistryEasysingle choice
Find the ratio of electron revolution frequency in He⁺ second excited state to H second state.
Options:
Answer:
A
Solution:
Bohr revolution frequency scales as Z²/n³. He⁺ in its second excited state has Z=2,n=3; H in its second state has Z=1,n=2. Ratio=(4/27)/(1/8)=32/27, A.
Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Bohr's Atomic Model
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
