Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic Structurede-Broglie's Wave EquationHard2 minQB

ChemistryHardnumerical

The de Broglie wavelength of the electron in the 3rd Bohr orbit of the hydrogen atom, in Å (up to two decimal places), is ( $r_{1} = 0.529$ Å)

Answer:

9.97

Solution:

$r_{3} = 0.529 \times 3^{2} = 4.761$ Å.

mvr = $nh /2 π$ and $λ = h / m v$ give $2 π r = nλ$ .

$λ = 2 π r / n = 2 \times 3.14 \times 4.761/3 = 9.97$ Å.

Answer: 9.97.

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:de-Broglie's Wave Equation

⏱ 2mℹ️ Source: QB

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