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Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureMiscellaneous/MixedMedium2 minQB

ChemistryMediumnumerical

Passage / Comprehension

The general electronic configuration of outer most and penultimate shell is given as (n -1)s²(n - 1)p⁶(n 1)d^xns² . Then for an element with n = 4 and x = 7

The number of unpaired electrons in the divalent cation of the element in isolated gaseous state is

Answer:

3.00

Solution:

$M : 3 s^{2} 3 p^{6} 3 d^{7} 4 s^{2}$

$M^{2 +} : 3 s^{2} 3 p^{6} 3 d^{7} 4 s^{0}$

The number of unpaired $e^{⊖} = 3$

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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