Chemistry - Atomic Structure Question with Solution | TestHub

Line E belong to visible so${\mathrm{n}}_1$will be 2.



For E,$\mathrm{\Delta }\mathrm{E}=+13.6\times {\mathrm{z}}^2\left(\frac{1}{4}-\frac{1}{9}\right)=13.6\times {\mathrm{z}}^2\times 0.138$

For D,$\mathrm{\Delta }\mathrm{E}=13.6\times {\mathrm{z}}^2\left(\frac{1}{9}-\frac{1}{36}\right)=13.6\times {\mathrm{z}}^2\times 0.083$

For C,$\mathrm{\Delta }\mathrm{E}=13.6\times {\mathrm{z}}^2\left(\frac{1}{16}-\frac{1}{36}\right)=13.6\times {\mathrm{z}}^2\times 0.034$

For A,$\mathrm{\Delta }\mathrm{E}=13.6\times {\mathrm{z}}^2\left(\frac{1}{4}-\frac{1}{25}\right)=13.6\times {\mathrm{z}}^2\times 0.21$

For B,$\mathrm{\Delta }\mathrm{E}=13.6\times {\mathrm{z}}^2\left(\frac{1}{9}-\frac{1}{25}\right)=13.6\times {\mathrm{z}}^2\times 0.07$

For$\mathrm{\Delta }\mathrm{E}$for A is larger than that of E, so it means line A belong to U.V. region.