Chemistry - Atomic Structure Question with Solution | TestHub

${\mathrm{I}}^{\mathrm{s}\mathrm{t}}\mathrm{ }$Bohr's orbit${\text{r}}_{\text{0}}\text{=}\text{0}\text{.529}\stackrel{\text{o}}{\text{A}}$of hydrogen
(i)$\mathrm{n}=2,\underset{(\mathrm{Z}=4)}{\mathrm{B}{\mathrm{e}}^{3+}}\therefore \mathrm{r}={\mathrm{r}}_0\times \frac{{\mathrm{n}}^2}{\mathrm{Z}}={\mathrm{r}}_0$
(ii)$\mathrm{n}=2,\underset{(\mathrm{Z}=3)}{\mathrm{L}{\mathrm{i}}^{2+}}\therefore \mathrm{r}={\mathrm{r}}_0\times \frac{2^2}{3}=\frac{4{\mathrm{r}}_0}{3}$
(iii)$\mathrm{n}=2,\underset{(\mathrm{Z}=2)}{\mathrm{H}{\mathrm{e}}^{+}}\therefore \mathrm{r}={\mathrm{r}}_0\times \frac{2^2}{2}=2{\mathrm{r}}_0$
(iv)$\mathrm{n}=3,\underset{(\mathrm{Z}=3)}{\mathrm{L}{\mathrm{i}}^{2+}}\therefore \mathrm{r}={\mathrm{r}}_0\times \frac{3^2}{3}=3{\mathrm{r}}_0$