Chemistry - Atomic Structure Question with Solution | TestHub

(A) $\Delta \mathrm{E}=13.6\times {\mathrm{Z}}^2\left[\frac{1}{{\mathrm{n}}_1^2}-\frac{1}{{\mathrm{n}}_2^2}\right]\mathrm{eV}=13.6\times 4\left[\frac{1}{4}-\frac{1}{16}\right]=10.2\mathrm{eV}$

(B) This transition is same as for H -atom from $\mathrm{n}=2$ to $\mathrm{n}=1$

(C) As for H-atom $\mathrm{n}=2$ to $\mathrm{n}=1$, so radiation emitting will be of UV region

(D) $\frac{1}{\lambda }=\bar{v}={\mathrm{R}}_{\mathrm{H}}\times {\mathrm{Z}}^2\left(\frac{1}{{\mathrm{n}}_1^2}-\frac{1}{{\mathrm{n}}_2^2}\right)$