Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureQuantum NumbersMedium2 minQB
ChemistryMediuminteger

Calculate :

Where,     

x = Maximum number of degenerate orbitals in 2nd excited state of Li2+     

y = Electronegativity value of most electronegative element on Pauling scale

Answer:
6
Solution:

To solve for , we first determine the values of and :

 

Find : Li²⁺ is a hydrogen-like (single-electron) species. In such systems, the energy of an orbital depends only on the principal quantum number ().

Ground state:

1ˢᵗ excited state:

2ⁿᵈ excited state:

For a given , the number of degenerate orbitals is . Thus, for , .

 

Find : The most electronegative element on the Pauling scale is Fluorine (F), which has an electronegativity value of approximately .

 

Calculation:

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Quantum Numbers
2mℹ️ Source: QB

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