Chemistry - Atomic Structure Question with Solution | TestHub
ChemistryAtomic StructureQuantum NumbersMedium2 minQB
ChemistryMediuminteger
Calculate :
Where,
x = Maximum number of degenerate orbitals in 2nd excited state of Li2+
y = Electronegativity value of most electronegative element on Pauling scale
Answer:
6
Solution:
To solve for , we first determine the values of and :
Find : Li²⁺ is a hydrogen-like (single-electron) species. In such systems, the energy of an orbital depends only on the principal quantum number ().
Ground state:
1ˢᵗ excited state:
2ⁿᵈ excited state:
For a given , the number of degenerate orbitals is . Thus, for , .
Find : The most electronegative element on the Pauling scale is Fluorine (F), which has an electronegativity value of approximately .
Calculation:
Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Quantum Numbers
⏱ 2mℹ️ Source: QB
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