Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic Structurede-Broglie's Wave EquationEasy2 minQB

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The de Broglie wavelength of a cricket ball of mass 150 g moving with a velocity of 20 m/s is approximately ( $h = 6.626 \times 1 0^{- 34}$ Js) :

Answer:

Solution:

$λ = h / (m v) = 6.626 \times 1 0^{- 34} / (0.150 \times 20) = 6.626 \times 1 0^{- 34} /3 = 2.2 \times 1 0^{- 34}$ m.

Answer: (A).

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:de-Broglie's Wave Equation

⏱ 2mℹ️ Source: QB

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