Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureRutherford's Atomic ModelMedium2 minQB

ChemistryMediumsingle choice

A proton and an α-particle are projected towards a stationary gold nucleus, in different experiments, with the same speed. The ratio of the distances of closest approach, dp : dα, is

Options:

Answer:

Solution:

$(1/2) m v^{2} = k Z e q / d$ , so $d = 2 k Z e q / (m v^{2})$ is proportional to q/m.

Proton: $q / m = 1/1$ . α-particle: $q / m = 2/4 = 1/2$ .

dp : dα = 1 : (1/2) = 2 : 1.

Trap: equal kinetic energy would give 1 : 2.

Answer: (B).

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Rutherford's Atomic Model

⏱ 2mℹ️ Source: QB

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