Chemistry - Atomic Structure Question with Solution | TestHub

$\lambda =h/(mv)=6.626\times 10^{-34}/(9.1\times 10^{-31}\times 1.09\times 10^6)=6.68\times 10^{-10}$ m.

Circumference = $2\pi r=2\times 3.14\times 2.116\times 10^{-10}=1.329\times 10^{-9}$ m.

Number of wavelengths = $1.329\times 10^{-9}/6.68\times 10^{-10}=1.99$, about 2. (This is the Bohr orbit $n=2.$)

Answer: (B).