The wave function of atomic orbital of H like species is given as ψ 2 s = 1 4 2 π Z 3 2 2 - Z r e - Z r 2 The radius for nodal surface for H e + ion in Å .

As at nodal surface ψ = 0 So 2 - Z r = 0 r = 2 Z = 2 2 = 1 Å

Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

The wave function of atomic orbital of H like species is given as
$ψ_{2 s} = \frac{1}{4 \sqrt{2} π} Z^{\frac{3}{2}} (2 - Z r) e^{- \frac{Z r}{2}}$
The radius for nodal surface for $H e^{+}$ ion in $Å$ .

Answer:

1.00

Solution:

As at nodal surface $ψ = 0$
So $2 - Z r = 0$
$r = \frac{2}{Z} = \frac{2}{2} = 1 Å$

Stream:NTA_ABHYASSubject:ChemistryTopic:Atomic StructureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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