In a multielectron atom, which of the following orbitals described by three quantum numbers will have same energy in absence of electric and magnetic fields? A. n = 1 , l = 0 , m 1 = 0 B. n = 2 , l

Question

In a multielectron atom, which of the following orbitals described by three quantum numbers will have same energy in absence of electric and magnetic fields?
A. $n = 1, l = 0, m_{1} = 0$
B. $n = 2, l = 0, m_{1} = 0$
C. $n = 2, l = 1, m_{1} = 1$
D. $n = 3, l = 2, m_{1} = 1$
E. $n = 3, l = 2, m_{1} = 0$
Choose the correct answer from the options given below:

TestHub · Accepted Answer

A : n = 1 , ℓ = 0 , m ℓ ​ = 0 B : n = 2 , ℓ = 0 , m ℓ ​ = 0 C : n = 3 , ℓ = 1 , m ℓ ​ = 1 D : n = 3 , ℓ = 2 , m ℓ ​ = 1 E : n = 3 , ℓ = 2 , m ℓ ​ = 0 ​ 1 s 2 s 3 p 3 d 3 d ​ In absence of electric and magnetic fields, all orbitals of 3d are degenerate

Chemistry - Atomic Structure Question with Solution | TestHub

Options:

Doubts & Discussion