Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureSpectrumMedium2 minPYQ_2024

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Number of spectral lines obtained in ${He}^{+}$ spectra, when an electron makes transition from fifth excited state to first excited state will be

Answer:

Solution:

The formula used here is:
Number of spectral lines $= \sum_{}^{} (n_{2} - n_{1})$
$n_{2}$ = Highest energy level=6(fifth excited state)
$n_{1}$ =Lowest energy level=2(first excited state)
Number of spectral lines
$= \sum_{}^{} (6 - 2) = 10$
Number of spectral lines in ${He}^{+}$ for transition from $n = 6$ to $n = 2$ are $10$

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Spectrum

⏱ 2mℹ️ Source: PYQ_2024

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