The number of correct statements from the following is ........... A. For 1 s orbital, the probability density is maximum at the nucleus B. For 2 s orbital, the probability density first increases to

Question

The number of correct statements from the following is ...........
A. For $1 s$ orbital, the probability density is maximum at the nucleus
B. For $2 s$ orbital, the probability density first increases to maximum and then decreases sharply to zero.
C. Boundary surface diagrams of the orbitals encloses a region of $100 %$ probability of finding the electron.
D. $p$ and $d$ -orbitals have $1$ and $2$ angular nodes respectively
E. probability density of $p$ -orbital is zero at the nucleus

TestHub · Accepted Answer

Probability density curves for 1 s , 2 s and 2 p orbitals are given below. For 1 s orbital, the probability density is maximum at the nucleus. For 2 s orbital, the probability density first decreases and then increases. At any distance from nucleus the probability density of finding electron is never zero, and it always have some finite value. The number of angular nodes are equal to azimuthal quantum number. For p - orbital it is equal to 1 and for d - orbital it is equal to 2. Probability density of p -orbital is zero at the nucleus

Chemistry - Atomic Structure Question with Solution | TestHub

Doubts & Discussion