Chemistry - Atomic Structure Question with Solution | TestHub

Formula for de-Broglie wavelength is

$\mathrm{\lambda }=\frac{\mathrm{h}}{\mathrm{p}}$or$\mathrm{\lambda }=\frac{\mathrm{h}}{\mathrm{m}\mathrm{v}}\Rightarrow \mathrm{e}\mathrm{V}=\frac{1}{2}\mathrm{m}{\mathrm{v}}^2$or$\mathrm{\nu }=\sqrt{\frac{2\mathrm{e}\mathrm{V}}{\mathrm{m}}}$

$\mathrm{\lambda }=\frac{\mathrm{h}}{\sqrt{2\mathrm{m}\mathrm{e}\mathrm{V}}}=\frac{6.62\times 10^{-34}}{\sqrt{2\times 9.1\times 10^{-31}\times 2.8\times 10^{-23}}}$

$=9.28\times 10^{-8}$$\mathrm{m}$