Chemistry - Atomic Structure Question with Solution | TestHub

Ferrous ion ($\mathrm{F}{\mathrm{e}}^{2+}$) changes to ferric ion${\mathrm{F}\mathrm{e}}^{3+}$on reacting with acidified${\mathrm{H}}_2{\mathrm{O}}_2$as.

$2{\mathrm{Fe}}^{2+}+{\mathrm{H}}_2{\mathrm{O}}_2+2{\mathrm{H}}^{+}⟶2{\mathrm{Fe}}^{3+}+2{\mathrm{H}}_2\mathrm{O}$

Electronic configuration of${\mathrm{F}\mathrm{e}}^{3+ }$$\mathrm{=\; 1}{\text{s}}^{2}2{\text{s}}^{2}2{\text{p}}^{6}3{\text{s}}^{2}3{\text{p}}^{6}3{\text{d}}^5$

Number of$\text{d}$-electrons = 5

Magnetic moment$= \sqrt{\mathrm{n}(\mathrm{n}+2)} = \sqrt{5(5+2)} = 5.92 \mathrm{BM}$