For an electron whose positional uncertainty is 1.0 × 1 0 - 10 m , the uncertainty in the component of the velocity in m s - 1 will be

According to uncertainty principle ⇒ δx × δp = h 4π ⇒ δp = h 4π × δx ⇒ mδv = h 4πδx δ v = h 4 π m δ x = 6.625 × 10 − 34 9.1 × 10 − 31 × 10 − 10 × 4 × 3.14 = 5.8 × 10 5

Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureMiscellaneous/MixedEasy2 minPYQ_2020

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For an electron whose positional uncertainty is $1.0 \times 1 0^{- 10} m$ , the uncertainty in the component of the velocity in m $s^{- 1}$ will be

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Answer:

Solution:

According to uncertainty principle
$\Rightarrow δx \times δp = \frac{h}{4π}$
$\Rightarrow δp = \frac{h}{4π \times δx}$
$\Rightarrow mδv = \frac{h}{4πδx}$
$δ v = \frac{h}{4 π m δ x}$
$= \frac{6.625 \times 10^{- 34}}{9.1 \times 10^{- 31} \times 10^{- 10} \times 4 \times 3.14} = 5.8 \times 10^{5}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Atomic StructureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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