Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructurePhotoelectric EffectMedium2 minPYQ_2020

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The work function of sodium metal is $4.41 \times 10^{- 19} J .$ If photons of wavelength $300 nm$ are incident on the metal, the kinetics energy of the ejected electrons will be $(h = 6.63 \times 10^{- 34} J s; c = 3 \times 10^{8} m s^{- 1})$ __________ $\times 10^{- 21} J$

Answer:

222

Solution:

$E = E_{0} + (kE)_{\max}$
$\frac{hC}{λ} = 4.41 \times 10^{- 19} + kE$
$\frac{6.63 \times 10^{- 34} \times 3 \times 10^{8}}{300 \times 10^{- 9}} = 4.41 \times 10^{- 19} + kE$
So, ${(KE)}_{\max} = 6.63 \times 10^{- 19} - 4.41 \times 10^{- 19}$

$= 2.22 \times 10^{- 19}$

$= 222 \times 10^{- 21} J$

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Photoelectric Effect

⏱ 2mℹ️ Source: PYQ_2020

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