Chemistry - Atomic Structure Question with Solution | TestHub

${\mathrm{\psi }}_{321}:\mathrm{n}=1,\mathrm{l}=2,\mathrm{m}=1$

Angular momentum$=\frac{\mathrm{h}}{2\mathrm{\pi }}\sqrt{\mathrm{l}(\mathrm{l}+1)}=\frac{\sqrt{6}\mathrm{h}}{2\mathrm{\pi }}$

Spherical nodes$=3-2-1=0;$Angular node$=2$

Sum of all the above$=\frac{\sqrt{6}\mathrm{h}}{2\mathrm{\pi }}+2=\frac{\sqrt{6}\mathrm{h}+4\mathrm{\pi }}{2\mathrm{\pi }}$