Chemistry - Atomic Structure Question with Solution | TestHub

$${\mathrm{IE}}_{{\mathrm{He}}^{+}}=13.6{\mathrm{Z}}_{{\mathrm{He}}^{+}}^2\left[\frac{1}{1^2}-\frac{1}{{\infty }^2}\right]=13.6{\mathrm{Z}}_{{\mathrm{He}}^{+}}^2\text{ where }\left({\mathrm{Z}}_{{\mathrm{He}}^{+}}=2\right)$$ Hence $13.6\times Z_{{\mathrm{He}}^{+}}^2=19.6\times 10^{-18}\mathrm{J}{\mathrm{atom}}^{-1}$. $${\left({\mathrm{E}}_1\right)}_{{\mathrm{L}}^{+2}}=-13.6{\mathrm{Z}}_{{\mathrm{Uj}}^{+2}}^2\times \frac{1}{1^2}=-13.6{\mathrm{Z}}_{{\mathrm{He}}^{+}}^2\times \left[\frac{{\mathrm{Z}}_{{\mathrm{L}}^{+2}}^2}{{\mathrm{Z}}_{{\mathrm{He}}^{+}}^2}\right]=-19.6\times 10^{-18}\times \frac{9}{4}=-4.41\times 10^{-17}\mathrm{J}/\text{ atom }$$