The uncertainty in position and velocity of a particle are 1 0 − 10 m and 5.27 × 1 0 − 24 ms − 1 respectively. Calculate the mass of the particle is ( h = 6.625 × 1 0 − 34 Js ) −

According to Heisenberg's uncertainty principle, Δ x ⋅ m Δ v = 4 π h or m = 4 π Δ x .Δ v h = 4 × 3.143 × 1 0 − 10 m × 5.27 × 1 0 − 24 ms − 1 6.625 × 1 0 − 34 Js ∵ [ J = Kgm 2 s 2 ] = 0.099 kg

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ChemistryAtomic StructureHeisensberg's Uncertainty PrincipleMedium2 minPYQ_2019

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The uncertainty in position and velocity of a particle are $1 0^{- 10} m$ and $5.27 \times 1 0^{- 24} ms^{- 1}$ respectively. Calculate the mass of the particle is $(h = 6.625 \times$ $1 0^{- 34} Js) -$

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Answer:

Solution:

According to Heisenberg's uncertainty principle, $Δ x \cdot m Δ v = \frac{h}{4 π}$ or $m = \frac{h}{4 π Δ x .Δ v}$ $= \frac{6.625 \times 1 0 ^{- 34} Js}{4 \times 3.143 \times 1 0 ^{- 10} m \times 5.27 \times 1 0 ^{- 24} ms ^{- 1}} ∵ [J = Kgm^{2} s^{2}] = 0.099 kg$

Stream:VITEEESubject:ChemistryTopic:Atomic StructureSubtopic:Heisensberg's Uncertainty Principle

⏱ 2mℹ️ Source: PYQ_2019

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