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ChemistryAtomic StructureBohr's Atomic ModelMedium2 minPYQ_2017
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The radius of the second Bohr orbit for hydrogen atom is

(Planck's constant,(h)=6.6262×1034Js;mass of electron=9.1091×10-31kg;charge of electron=1.60210×10-19C;permittivity of vacuum,(0)=8.854185×10-12kg-1m-3A2)

Options:

Answer:
C
Solution:

Radius of the Bohr's orbit is calculated by the following formula rn=0.529×n2z

Radius is directly proportional to square of nth orbit and inversely proportional to atomic number. This formula works for single electron species

here rn=radius of the nth orbit

Z=1 and n=orbit or shell number

r2=0.529×221 Å

=2.12 

 

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Bohr's Atomic Model
2mℹ️ Source: PYQ_2017

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