Chemistry - Atomic Structure Question with Solution | TestHub

According to de-Broglie's equation. $$\lambda =\frac{h}{mv}\Rightarrow {\lambda }^2=\frac{h^2}{m^2{v}^2}$$ or $m{v}^2=\frac{h^2}{m{\lambda }^2}$ $$\begin{array}{l}\because \mathrm{KE}(K)=\frac{1}{2}m{v}^2\\ \therefore \mathrm{KE}(K)=\frac{1}{2}\frac{h^2}{m{\lambda }^2}\end{array}$$ $$\begin{array}{l}\Rightarrow \frac{K_1}{K_2}={\left(\frac{{\lambda }_2}{{\lambda }_1}\right)}^2={\left(\frac{5}{3}\right)}^2\\ \therefore K_1:K_2=25:9\end{array}$$