Chemistry - Aromatic Hydrocarbon Question with Solution | TestHub

Question Explanation:

The question asks about (Z) in C₆H₅Z predominantly ortho/para directing in electrophilic substitution

reactions.

Concept:

This question is based on electrophilic substitution and directive influence of substituents.

Solution:

–NO₂ , –COOH and –CN are strong electron withdrawing groups (– M) and meta directing. –Cl is

deactivating but ortho/para directing. While –OH, –OMe, –NH₂ , –NHCOCH₃ , and –CH₃ are electron

releasing and ortho/para directing. The option in which both groups are ortho/para directing is –

NHCOCH₃ and –CH₃ .

Final Answer:

The correct option is (D)