In the Kjeldahl's method for estimation of nitrogen present in a soil sample, ammonia evolved from 0.75 g of sample neutralized 10 mL of ${1M H}_{2} S O_{4} .$ The percentage of nitrogen in the soil is
[Report your answer upto two decimal places]

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TestHub · Accepted Answer

In 0.75 g of sample the percentage of nitrogen can be find out as follows
$N % = \frac{14 \times N \times V}{W_{O . C .}} \times 100$
Here $N \times V$ of $H_{2} S O_{4} = n \times M \times V$
$= 2 \times 1 \times 10 \times 1 0^{- 3} = 20 \times 1 0^{- 3}$
% Nitrogen $= \frac{14 \times 20 \times 1 0^{- 3}}{0.75} \times 100 = 37.33 %$

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