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ChemistryAMINESCHEMICAL REACTIONS OF AMINESMedium2 minQB
ChemistryMediuminteger

From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be .

Answer:
95
Solution:

Explanation Question: Asking about the amount of acetanilide obtained from 6.55 gram anilne.

Concept:

Based on acetylation reaction and mole-mole analysis

Explanation Question:   Asking about the amount of acetanilide obtained from 6.55 gram anilne .

Concept:

Based on acetylation reaction and mole-mole analysis

Solution:

image.png(Aniline)                          Consider 100% yield to get maximum amount of the product

93 gram ( 1 mole) of  aniline will fill form 135 gram of acetanilide.

so 6.55 gram of aniline will form 135 / 93 × 6.55 

gram acetanilide

= 9.5 gram

= 95 × 10 gram

Correct answer is 95

Final Answer :- 95

Stream:JEESubject:ChemistryTopic:AMINESSubtopic:CHEMICAL REACTIONS OF AMINES
2mℹ️ Source: QB

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