Chemistry - AMINES Question with Solution | TestHub

Butanoic acid undergoes Hell-Volhard-Zelinsky alpha bromination with $\mathrm{B}{\mathrm{r}}_2$/red P to 2-bromobutanoic acid X. $\mathrm{N}{\mathrm{H}}_3$ substitutes Br and mild acid work-up gives 2-aminobutanoic acid Y. Acetyl chloride protects its amino group to give N-acetyl-2-aminobutanoic acid Z. This is HVZ, not decarboxylative Hunsdiecker. Thus A,B,C.