Chemistry - AMINES Question with Solution | TestHub

$\underset{\begin{array}{c}\text{ Mol.wt.45g }\end{array}}{{\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NH}}_2}\stackrel{{\mathrm{NaNO}}_2+\mathrm{HCl}}{\to }\stackrel{{\mathrm{H}}_2\mathrm{O}}{\to }{\mathrm{CH}}_3{\mathrm{CH}}_2-\mathrm{OH}+\underset{14\mathrm{g}}{{\mathrm{N}}_2}$ given : ${\mathrm{N}}_2$ evolved is 2.24 L i.e. 0.1 mole. i.e. ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NH}}_2$ (ethyl amine) will be $4.5\mathrm{g}$ $(=0.1\mathrm{mole})$ Hence the answer $=45\times 10^{-1}\mathrm{g}$