Chemistry - AMINES Question with Solution | TestHub

Lithium aluminium hydride is a strong reducing agent. It converts amides, cyanides and isocyanides to amines.

${\mathrm{CH}}_3{\mathrm{CONH}}_2\underset{\left(\mathrm{ii}\right) {\mathrm{H}}_3{\mathrm{O}}^{+}}{\overset{\left(\mathrm{i}\right) {\mathrm{LiAlH}}_4}{\to }}{\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NH}}_2\left(\mathrm{primary} \mathrm{amine}\right)$

${\mathrm{CH}}_3\mathrm{CN}\underset{\left(\mathrm{ii}\right) {\mathrm{H}}_3{\mathrm{O}}^{+}}{\overset{\left(\mathrm{i}\right) {\mathrm{LiAlH}}_4}{\to }}{\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{NH}}_2\left(\mathrm{Primary} \mathrm{amine}\right)$

${\mathrm{CH}}_3\mathrm{NC}\underset{\left(\mathrm{ii}\right) {\mathrm{H}}_3{\mathrm{O}}^{+}}{\overset{\left(\mathrm{i}\right) {\mathrm{LiAlH}}_4}{\to }}{\mathrm{CH}}_3{\mathrm{NHCH}}_3\left(\mathrm{Secondary} \mathrm{amine}\right)$

In Hoffmann bromamide reaction, primary amides converts to primary amines with loss of one carbon.

${\mathrm{CH}}_3{\mathrm{CONH}}_2\stackrel{{\mathrm{Br}}_2/\mathrm{KOH}}{\to }{\mathrm{CH}}_3{\mathrm{NH}}_2$