X → KOH+CHCl 3 Y → LiAlH 4 CH 3 CH 2 NHCH 3 Identify compound X

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ChemistryAMINESMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

$(X) \overset{{KOH+CHCl}_{3}}{\to} (Y) \overset{{LiAlH}_{4}}{\to} {CH}_{3} {CH}_{2} {NHCH}_{3}$ Identify compound X

Options:

Answer:

Solution:

In this conversion X is ethylamine, Y is ethyl isocyanide and the final product is N-methyl-ethamine

$\underset{(X)}{C H_{3} - C H_{2} - N H_{2}} \to \underset{(Y)}{C H_{3} - C H_{2} N C} \to C H_{3} - C H_{2} - N H - C H_{3}$

Stream:NTA_ABHYASSubject:ChemistryTopic:AMINESSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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